How much force is in this bar? Am I correct?

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SUMMARY

The discussion centers on calculating the forces in a bar suspended by two threads, with a mass of 15 kg. The force in thread L1 is given as 49 N, leading to the calculation of force in thread L2 as 98.15 N based on the total weight of the bar (147.15 N). The conclusion emphasizes that the system is in equilibrium, meaning the sum of forces equals zero, and the differing forces in L1 and L2 are explained through the concept of torque, which will be explored in future studies.

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Homework Statement



Once again I am having trouble with a rather simple problem.



This bar above with the mass of 15 Kgs hangs in 2 threads/wires. The force in L1 is 49 N, what is the force in L2?


Homework Equations





The Attempt at a Solution



My solution is this; 1 Kg here on Earth is 9.81 Newtons. So by simply multiplying 15kg with 9.81 I get 147.15 N. The force in L1 is 49 N so is the force in L2 should be 98.15 N?

Homework Statement



I am new to physics but I find it very interesting. The thing I wonder about, according to my solution the major force is in L2 with 98.15 N and by looking at the picture L1 seems to be carrying the major part of the bar so shouldn't L1 have the most force?

Homework Equations





The Attempt at a Solution



 
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Your solution is correct. Because the bar is in equilibrium, the sum of all the forces must be zero.

As to why there are different forces in L1 and L2, that you will learn later, when you come to torques (A.K.A. moments of forces).
 
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