How Much Force is Needed to Climb a Hill at Constant Speed with Air Resistance?

  • Thread starter Thread starter hemetite
  • Start date Start date
  • Tags Tags
    Hill
Click For Summary
SUMMARY

A bicyclist with a total mass of 65 kg must exert a force of 133 N to climb a 6-degree hill at a constant speed of 6 km/h, accounting for air resistance. The force due to gravity acting down the slope is calculated as mg sin(6), resulting in a force of 66.58 N. The total force required to overcome both gravity and air resistance is thus 66.58 N + 66.58 N = 133 N. The discrepancy with the model answer of 130 N may be due to rounding to two significant figures.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic trigonometry, specifically sine functions
  • Knowledge of forces, including gravitational and air resistance forces
  • Familiarity with the concept of constant speed and net force
NEXT STEPS
  • Study the principles of Newton's second law of motion
  • Learn about the effects of air resistance on moving objects
  • Explore the calculations of forces on inclined planes
  • Investigate rounding techniques in physics problem-solving
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and forces, as well as educators looking for examples of force calculations in real-world scenarios.

hemetite
Messages
50
Reaction score
0

Homework Statement


A bicyclist of mass 65kg (including the bicycle) can coast down a 6 degree hill at steady speed of 6km/h because of air resistance. How much force must be applied to climb the hill at the same speed and same air resistance?


The Attempt at a Solution



since it is at constant speed. the net force is zero.

therefore the

Fg (force due to mg) - Fr (air resistance force) = 0

(mg sin 6) - Fr = 0

Fr= mg sin 6 = 66.58N.

For it to climb back the hill at the same speed and same air restance?

the bicyclist have to tackle the two same force now = 66.58 + mg sin 6 = 133N.

The model answer given is 130N...but i got 133N...

any mistake i have made?
 
Physics news on Phys.org
hemetite said:

Homework Statement


A bicyclist of mass 65kg (including the bicycle) can coast down a 6 degree hill at steady speed of 6km/h because of air resistance. How much force must be applied to climb the hill at the same speed and same air resistance?


The Attempt at a Solution



since it is at constant speed. the net force is zero.

therefore the

Fg (force due to mg) - Fr (air resistance force) = 0

(mg sin 6) - Fr = 0

Fr= mg sin 6 = 66.58N.

For it to climb back the hill at the same speed and same air restance?

the bicyclist have to tackle the two same force now = 66.58 + mg sin 6 = 133N.

The model answer given is 130N...but i got 133N...

any mistake i have made?
You haven't made any mistakes, perhaps the model answer has rounded to 2sf?
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 39 ·
2
Replies
39
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
3
Views
6K
Replies
4
Views
8K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 6 ·
Replies
6
Views
4K
Replies
2
Views
3K