How Much Force is Needed to Move a 50kg Box with Friction and Acceleration?

[sbesner]

Hello everyone... I have been having some issues with this one particular... I'm sure its very simple, I just can't rap my head around it!Calculate the horizontal force required to move a 50kg box across level floor with an acceleration of 0.620 m/s/s if coefficient of friction is 0.110

FORCE = ??

I think its the acceleration that is throwing me off here. Would i need to find my Frictional force then determine my Fnet?

Thanks in advance for the aid.

-Stephan

 

[vissh]

Hello >:D
Hmm a basic question indeed :D
The block is lying on rough horizontal surface.When an Force is applied, the Static friction,f_s will come into play and try to oppose the relative motion.f_s will increase as applied force is increased.But f_s got a max. value (coef. of friciton)*(normal rxn by surface applying frictional force) and after that Kinetic friction will act and have value same as (coef. of friciton)*(normal rxn by surface applying frictional force)
Let the force applied Be F , Kinetic friction in opposite direction of F and apply Newton's second law .
U will get the answer :D

Hope this helps:)

 

[jmb88korean]

Knowing both mass and acceleration you should find fnet using F=ma. This value plus the frictional force must equal the applied force so simply use the mass to find the normal force to get frictional force.

 

[Paulie323]

this is a easy problem al this means is to move the box forward your applied force will be Fnet+Ff.
hope this helps!

 

[rwisz]

ie

Hello Stephanie,

In order to calculate the horizontal force required to move the 50kg box across the level floor, we first need to understand the forces at play. There are two main forces acting on the box: the applied force (F) and the frictional force (Ff). The applied force is the force that you need to exert on the box to make it move, and the frictional force is the force that opposes the motion of the box.

The equation for calculating the net force (Fnet) is Fnet = ma, where m is the mass of the box and a is the acceleration. In this case, the acceleration is given to be 0.620 m/s/s. Therefore, Fnet = (50kg)(0.620 m/s/s) = 31 N.

Now, we need to take into account the coefficient of friction (μ) which is given to be 0.110. The formula for calculating the frictional force is Ff = μN, where N is the normal force. In this case, the normal force is equal to the weight of the box, which is mg = (50kg)(9.8 m/s/s) = 490 N. Therefore, Ff = (0.110)(490 N) = 53.9 N.

To find the applied force, we can use the equation F = Fnet + Ff. Substituting the values we have calculated, we get F = 31 N + 53.9 N = 84.9 N.

Therefore, the horizontal force required to move the 50kg box across the level floor with an acceleration of 0.620 m/s/s and a coefficient of friction of 0.110 is 84.9 N.

I hope this helps clear up any confusion you may have had. Let me know if you have any further questions.

Best,