How Much Force is Needed to Move a 50kg Box with Friction and Acceleration?

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Homework Help Overview

The discussion revolves around calculating the horizontal force required to move a 50kg box across a level floor, considering an acceleration of 0.620 m/s² and a coefficient of friction of 0.110. Participants are exploring the dynamics of force, friction, and acceleration in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to incorporate friction and acceleration into the calculation of the required force. Some participants suggest using Newton's second law and considering both the net force and frictional force in their reasoning.

Discussion Status

Participants are actively engaging with the problem, offering various insights into the relationship between applied force, friction, and acceleration. There is a mix of interpretations regarding how to approach the calculation, with no explicit consensus reached yet.

Contextual Notes

Some participants note the importance of distinguishing between static and kinetic friction, as well as the need to calculate the normal force to determine the frictional force accurately. The original poster expresses uncertainty about the role of acceleration in the problem.

sbesner
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Hello everyone... I have been having some issues with this one particular... I'm sure its very simple, I just can't rap my head around it!Calculate the horizontal force required to move a 50kg box across level floor with an acceleration of 0.620 m/s/s if coefficient of friction is 0.110

FORCE = ??

I think its the acceleration that is throwing me off here. Would i need to find my Frictional force then determine my Fnet?

Thanks in advance for the aid.

-Stephan
 
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Hello >:D
Hmm a basic question indeed :D
The block is lying on rough horizontal surface.When an Force is applied, the Static friction,fs will come into play and try to oppose the relative motion.fs will increase as applied force is increased.But fs got a max. value (coef. of friciton)*(normal rxn by surface applying frictional force) and after that Kinetic friction will act and have value same as (coef. of friciton)*(normal rxn by surface applying frictional force)
Let the force applied Be F , Kinetic friction in opposite direction of F and apply Newton's second law .
U will get the answer :D

Hope this helps:)
 
Knowing both mass and acceleration you should find fnet using F=ma. This value plus the frictional force must equal the applied force so simply use the mass to find the normal force to get frictional force.
 
this is a easy problem al this means is to move the box forward your applied force will be Fnet+Ff.
hope this helps!
 

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