How Much Heat is Lost from a Swimming Pool?

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SUMMARY

The discussion focuses on calculating the heat loss from a swimming pool over a four-hour period. The pool's temperature drops from 32ºC to 26ºC, and it contains 1200 liters of water. Using the formula q = mvΔT, where m is the mass of the water (1200 kg), v is the specific heat of water (4.186 J/gºC), and ΔT is the change in temperature (6ºC), the total heat loss is calculated to be 286,800,000 J.

PREREQUISITES
  • Understanding of specific heat capacity
  • Familiarity with the formula q = mvΔT
  • Basic knowledge of temperature measurement in Celsius
  • Concept of mass and volume relationship in water (1 liter = 1 kg)
NEXT STEPS
  • Learn about heat transfer principles in fluids
  • Explore specific heat capacities of different materials
  • Research methods to minimize heat loss in swimming pools
  • Study the effects of environmental factors on pool temperature
USEFUL FOR

Students in physics or environmental science, pool maintenance professionals, and anyone interested in thermodynamics related to water bodies.

purehavoccc
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would anyone know how to do this by any chance?:rolleyes:

The temperature of a swimming pool is 32ºC at 2 p.m. in the afternoon. At 6 p.m., its temperature decreases to 26ºC. Given the pool contains 1200 liters of water and water’s specific heat is 4.186 J/gºC. How much heat does the pool lose to the atmosphere in 4 hours? (Assume 1 lit = 1 kg.)

50.208 J

40.116 J

286800000 J

5776800000 J

57768 J

i have no clue as to which one it is and i need to turn in this exam soon =/
thanks a lot, i just need a little help.
 
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use waters density to find out how many grams of H20 you have then use
q=mvdeltaT to find q.

Hope this helps.
 

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