How Much HNO3 to Neutralize 0.200 M NaOH?

[protractor]

Homework Statement

What volume in milliliters of .500 M HNO₃ is required to neutralize 40.00 milliliters of a 0.200 M NaOH solution?

Homework Equations

The balanced chemical equation
HNO₃(aq) + NaOH(aq) → H₂O(l) + NaNO₃(aq)

The Attempt at a Solution

.200 mol NaOH/1L x 0.04000 L x 1 mol HNO₃/ 1 mol NaOH x 1L/ 0.500 mol HNO₃ x 1 mL/(10^-3) L = 16.0 mL

I'm not sure if the procedure is correct.

 

[Borek]

A bit convoluted if you ask me (I don't like this approach to stoichiometry, not your fault), but at least it yields a correct answer.