How much is the current flowing in the transmission line?

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SUMMARY

The current flowing in the transmission line from a small power plant producing 6.0 kV and 150 A is calculated using the transformer ratio. The voltage is stepped up to 240 kV before reaching the substation. The relationship I(p)/I(s) = V(s)/V(p) indicates that the primary current I(p) is 150 A, while the secondary current I(s) can be determined using the voltage ratio. The resistance of the transmission line (75 ohms) does not impact the current calculation in this context, as it only affects voltage drop downstream.

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golriz
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Asmall power plant produces a voltage of 6.0kV and a current of 150A. The voltage is stepped up to 240kV by a transformer before being sent to a substation. The resistance of the transmission line between the power plant and the substation is 75 ohm. How much is the current flowing in the transmission line?


I(p)/I(s)= V(s)/V(p) s= stationary P= primary
V= IR


I(p) = 150 , V(p) = 6.0kV , V(s) = 240kV , I(s) = ?
 
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golriz said:
I(p)/I(s)= V(s)/V(p) s= stationary P= primary

I(p) = 150 , V(p) = 6.0kV , V(s) = 240kV , I(s) = ?

Plug in the numbers and solve. V = IR is not needed here.
 
oh, why?
I don't know why V = IR is not needed here?
 
It occurred to me (after discussing this with somebody else) that I may not understand the layout here.

Perhaps you have a figure you can look at to answer this question: is the 75 ohm line in between the power plant and the transformer, or is it between the transformer and the substation?
 
I think it is between the transformer and the substation.
 
In that case, the 75Ω will affect the voltage at the substation, but not at the transformer. It is irrelevant here.

I'm not sure why they included that information, maybe just to throw you off?
 
Last edited:

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