How Much Mass Does the Sun Lose Each Day?

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SUMMARY

The Sun loses approximately 3.84 x 1014 kg of mass each day due to its energy output of 4 x 1026 W, calculated using Einstein's equation E = mc2. The energy produced from the fusion of hydrogen nuclei into helium is not necessary for this calculation, as the problem focuses solely on the energy radiated. The energy output over one day is calculated as 3.456 x 1031 J, leading to the mass loss calculation.

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Homework Statement


The sun radiates energy at the rate of approximately 4 x 10^26 W. Assume that this energy is produced by a reaction whose net result is the fusion of 4 H nuclei to form 1 He nucleus, with the release of 25 MeV for each He nucleus formed.

Calculate the sun's loss of mass per day


Homework Equations



E = mc^2



The Attempt at a Solution



I think all the information about the Helium reaction is a red herring, but I'm
not sure. It's throwing me off. The problem says that the sun radiate energy
at the rate of 4x10^26 W, but it doesn't say in what time frame.
What I did at first, was assumed that that rate is per second and I did as follows;

1 day = 24 hours = 24*60 minutes = 24*60*60 seconds = 86400 s

Energy output in a day = 4x10^26 W/s * 86400s = 3.456 * 10^31 J

then I used E = mc^2 -> m = E/c^2 = 3.456 * 10^31 J/(2.0 * 10^8 m/s)^2
= 3.84 * 10^14 kg to be the amount of mass the sun loses every day.

Is this right, or do I have to use the given information about the Helium reaction?
 
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I believe you are correct, its only asking for a mass equivalent of x amt of energy.
 

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