How Much Mass is Needed to Prevent the Wheel from Rotating?

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SUMMARY

The discussion focuses on calculating the mass required to prevent a large wheel from rotating, given its radius of 7.1 m and a hanging box of 7.6 kg. The correct mass, denoted as M, is determined to be 39 kg. The calculations involve setting the sum of torques to zero, utilizing the equation m1r1^2 + m2r2^2 = 0, where m1 is the mass of the box and m2 is the mass to be calculated. The final solution confirms that the mass M must be 39 kg to maintain equilibrium.

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hey123a
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Homework Statement


A large wheel has a radius of 7.1 m. A rope is wrapped around the edge of the wheel and a 7.6 kg box hangs from the rope. A smaller disk of radius 1.38 m is attached to the wheel. A rope is wrapped around the edge of the disk as shown. An axis of rotation passes through the center of the wheel-disk system. What is the value of the mass M that will prevent the wheel from rotating?


Homework Equations





The Attempt at a Solution


all moments of inertia should equal zero so
m1r1^2 + m2r2^2 = 0
m1 = -m2r2^2/r1^2
m1 = -(7.6)(7.1)^2/1.38^3
m1 = 201

answer is actually 39kg
 
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hey123a said:

Homework Statement


A large wheel has a radius of 7.1 m. A rope is wrapped around the edge of the wheel and a 7.6 kg box hangs from the rope. A smaller disk of radius 1.38 m is attached to the wheel. A rope is wrapped around the edge of the disk as shown. An axis of rotation passes through the center of the wheel-disk system. What is the value of the mass M that will prevent the wheel from rotating?


Homework Equations





The Attempt at a Solution


all moments of inertia should equal zero so
m1r1^2 + m2r2^2 = 0
[/QUOTE]

The torques have to sum up to zero.

ehild
 

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