How Much Power Does the Elevator Cable Exert in kW?

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SUMMARY

The discussion centers on calculating the average power exerted by an elevator cable when moving a loaded cab with a mass of 3,000 kg up a shaft. The cab ascends 165 meters in 23 seconds at a constant speed. Using the formula P = Fv, where P is power, F is force, and v is velocity, the average power can be determined. The force exerted by the cable equals the weight of the cab, and the velocity can be calculated from the distance and time.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Basic knowledge of power calculation in physics
  • Familiarity with the formula P = Fv
  • Ability to perform unit conversions (e.g., from m/s to kW)
NEXT STEPS
  • Calculate the force exerted by the elevator cable using F = mg
  • Determine the velocity of the elevator cab using v = d/t
  • Apply the power formula P = Fv to find the average power in kW
  • Explore real-world applications of elevator power calculations in engineering
USEFUL FOR

Physics students, mechanical engineers, and anyone involved in elevator design or maintenance will benefit from this discussion.

needhelp1234
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The loaded cab of an elevator has a mass of 3.0 103 kg and moves 165 m up the shaft in 23 s at constant speed. At what average rate does the force from the cable do work on the cab?


I don't even know where to begin. The answer is in kW
 
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Employ a formula to calculate power:

P = Fv
 

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