How Much Steam Is Needed to Melt Ice into Water at 20 Celsius?

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SUMMARY

The discussion focuses on calculating the mass of steam at 100°C required to convert 1.00 kg of ice at 0°C into liquid water at 20°C. The relevant equations include Q = mL for latent heat and Q = mc(deltaT) for temperature change. The heat needed to melt the ice and raise the temperature of the resulting water is derived from the steam, which releases latent heat and then cools. The problem emphasizes the importance of distinguishing between the latent heats of fusion and vaporization.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically heat transfer.
  • Familiarity with specific heat capacities: ice (2100 J/kg·K), water (4190 J/kg·K), and steam (2010 J/kg·K).
  • Knowledge of latent heat values: latent heat of fusion (333,000 J/kg) and latent heat of vaporization (2,260,000 J/kg).
  • Ability to manipulate and solve equations involving energy balance.
NEXT STEPS
  • Calculate the heat required to melt ice using Q = mL.
  • Determine the heat needed to raise the temperature of water from 0°C to 20°C using Q = mc(deltaT).
  • Learn about the concept of energy conservation in phase changes.
  • Explore the differences between latent heat of fusion and latent heat of vaporization.
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone involved in heat transfer calculations in physical chemistry or engineering contexts.

engineer2010
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Homework Statement



What mass of steam at 100 celsius must be added to 1.00 kg of ice at 0 celsius to yield liquid water at 20 celsius.


Homework Equations



Q = mL
Q = mc(deltaT)
change in energy = 0

The Attempt at a Solution



Ice
m= 1.00
c = 2100
T1 = 0
Tf =
L = 333

water
m=
c = 4190
T1 =
Tf= 20

Steam
m = ?
c = 2010
L = 2260
T1 = 100
Tf =

I am stil missing some of the needed information and i am not sure how to organize my equations.
 
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Divide into two parts.

How much heat is needed to melt the ice?

How much heat is needed to raise the temp of this water from 0 C to 20 C?

This whole heat is supplied by a certain amount of steam, which first gives up the latent heat of evaporation, and then cools from 100 c to 20 C. Equate this to the sum of the first two.

(Remember, there are two kinds of latent heat involved here. Don't mix them up)
 

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