How much stored energy do the plates have?

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SUMMARY

The stored energy in two parallel circular plates with a radius of 7.0 mm and a surface charge of Q = 4.618 x 10-10 C, separated by a distance of d = 1.0 mm, is calculated to be approximately 78 nJ. The area of the plates is determined using the formula A = π r2, resulting in an area of 1.539 x 10-4 m2. The capacitance is derived from the equation C = ∈0⋅A / d, where ∈0 = 8.85 x 10-12 F/m. The potential energy (PE) is computed using PE = 1/2 ⋅ Q2 / C, confirming the energy stored in the plates.

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ikihi
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Homework Statement


Two parallel circular plates with radius 7.0 mm carrying equal magnitude surface charge of Q = 4.618 x 10-10 C are separated by a distance of d = 1.0 mm (0.001 m). How much stored energy do the plates have?

Homework Equations


Acircle = π r2
C = ∈0⋅A / d
PE = 1/2 ⋅ Q2 / C
PE = 1/2 ⋅ [(Q2⋅d) / (∈0⋅A)]
0 = 8.85 x 10^-12

The Attempt at a Solution


[/B]
Area = π ⋅ (0.007)2
Area = 1.539 x 10-2 m2

PE = 1/2 ⋅ [((4.618x10-10)2⋅0.001) / (8.85x10-12 ⋅1.539 x 10-4)]
PE = 7.829 x 10-8 J

PE ≈ 78 nJ
(is this correct?)
 
Last edited:
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ikihi said:
C = 1/2 ⋅ [((4.618x10-10)2⋅0.001) / (8.85x10-12 ⋅1.539 x 10-4)]
C = 7.829 x 10-8 J

C ≈ 78 nJ
(is this correct?)

Other than using the variable C for energy your result looks good. :smile:
 
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