Parallel-Plate Capacitor Separation

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 1K views
beeteep
Messages
11
Reaction score
0

Homework Statement


A parallel-plate capacitor has a plate area of 18.5 cm2 and a capacitance of 4.8 pF
What is the plate separation? The value of the permittivity of a vacuum is 8.8542 x 10-12 C2/N⋅m2

Homework Equations


C = κε0 (A/d)

The Attempt at a Solution


4.8x10-12 = ((8.8542x10-12)(1)(.185)) / d

d = .341255625 m
 
Physics news on Phys.org
I didn't know there was a difference between converting between cm2 and m2. I'll need to do a little more digging on how to properly convert between those, but you are correct. That was my issue. Thanks for your help!