How much tension must a rope withstand if it is used to accelerate a 1400 kg car

Click For Summary

Homework Help Overview

The problem involves calculating the tension in a rope used to accelerate a 1400 kg car vertically upward at an acceleration of 0.50 m/s². The context includes forces acting on the car, particularly gravitational force and tension.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the forces acting on the car, including gravitational force and tension. There are attempts to apply Newton's Second Law and clarify the relationship between these forces. Questions arise about whether to add or subtract forces in the calculations.

Discussion Status

Participants are exploring the correct application of Newton's Second Law and the relationship between tension and gravitational force. Some guidance has been provided regarding the upward force being the tension in the rope, and there is an ongoing clarification of how to combine the forces involved.

Contextual Notes

There is some confusion regarding the roles of different forces, particularly the normal force and how it applies when the car is accelerating vertically. Participants are also grappling with the implications of the car's weight and the acceleration on the tension calculation.

mortho
Messages
99
Reaction score
0
[SOLVED] Rope Forces

Homework Statement


How much tension must a rope withstand if it is used to accelerate a 1400 kg car vertically upward at 0.50 m/s2?



Homework Equations



F=ma

The Attempt at a Solution



Well i know that the force going up is going to be 700 N and i need to somehow subtract it from a force going horizontally to get my answer. I just don't know which..maybe I'm just missing something that i can 't think of ..NEED HELp thanks!
 
Physics news on Phys.org
What are the forces acting vertically? Let's say we pick upward to be positive, what's the equation for Newton's Second Law in terms of the summed forces?
 
Fg and Fn are acting vertically. the equation for Fg is Fg=mg and so i got 13720. Fg must be equal to Fn because of the flat ground so would that be that answer. But then the acceleration's going to affect it so...then 700 N is going to play a part right? Do i subtract it?? I'm so confused!
 
Ok, so you're going to have the force on the car due to gravity, this is the car's weight. But I believe you're mistaken about the second force. We're not going to have a normal force, as the car won't be on the ground once it accelerates vertically. What force is pulling the car upwards, where does it fit into our net force equation?

You've already identified the weight force, now we need one more:

[tex]\Sigma F_{vert} = (Upward force) - mg = ma[/tex]
 
i don't understand the upward force part..would we do this 700-13720 because 700 is what was pushing down but since it's lifted it lessens?
 
The upward force is the tension in the rope. Imagine the car hanging from a crane (or something). If it is being pulled upwards, there are two forces present. The tension, and gravity. They are acting in different directions. You need to add them up according to Newton's second law to get the net force, which will equal ma. You know the mass and acceleration, all you need to do is solve for the tension (or the upward force as hotcommodity called it). Look at post #4 carefully.
 
so i don't subtract 700 from 13720? i would add them instead?
 
mortho said:
so i don't subtract 700 from 13720? i would add them instead?

Yes, that's right.
 
and that would be my final answer? wow that's huge!
 
  • #10
Yes, that's what your answer will be.
 
  • #11
THANK YOU ! oh by the way i sent you a message in your inbox thing!
 
  • #12
Got it.
 

Similar threads

  • · Replies 38 ·
2
Replies
38
Views
5K
Replies
43
Views
5K
Replies
11
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 25 ·
Replies
25
Views
6K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 39 ·
2
Replies
39
Views
7K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
8K
  • · Replies 8 ·
Replies
8
Views
9K