How Much Vertical Acceleration Does a Jet Need to Avoid a Hill?

In summary, the vertical acceleration required for a jet to avoid a hill depends on several factors, including the aircraft's speed, altitude, and the height of the hill. The necessary vertical acceleration can be calculated using principles of physics, taking into account the jet's flight path and the need to achieve a specific altitude before reaching the obstacle. Proper calculations ensure that the jet maintains safe operational parameters while navigating terrain.
  • #1
KukyZ
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New user has been reminded to please always show their work on schoolwork problems.
Homework Statement
A jet travels at speeds of 1300 km/h at 35 m above ground level. Suddenly it meets a slope of 10% and immediately corrects its trajectory accelerating upwards (a(t) constant, in the direction of y).
How much should the acceleration be worth to avoid impact with the ground?
Relevant Equations
x=V
y=35+1/2 at^2
The answer should be 10 m/s^2 but I don't know how to solve it
 
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  • #2
I guess you meant x=vt.
So you have the position of the jet at time t. What about the position of the ground below it?
 
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  • #3
KukyZ said:
Homework Statement: A jet travels at speeds of 1300 km/h at 35 m above ground level. Suddenly it meets a slope of 10% and immediately corrects its trajectory accelerating upwards (a(t) constant, in the direction of y).
How much should the acceleration be worth to avoid impact with the ground?
Relevant Equations: x=V
y=35+1/2 at^2

The answer should be 10 m/s^2 but I don't know how to solve it
I suspect that the problem is asking for the smallest possible vertical acceleration that will prevent a collision with the ground. Start by drawing a diagram of the jet's trajectory. The jet must barely graze the hillside.

How do you know that the answer is 10 m/s2?
 
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