How Much Weight Must Block C Have to Prevent Block A from Sliding?

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SUMMARY

The discussion centers on the mechanics of three blocks, A, B, and C, with specific weights of 45 N, 25 N, and an unknown weight, respectively. To prevent block A from sliding, the minimum weight of block C must be 20 N, calculated using the static friction coefficient of 0.20. When block C is removed, the acceleration of block A is determined to be 2 m/s², factoring in the kinetic friction coefficient of 0.15. The analysis emphasizes the importance of understanding forces and friction in static and dynamic scenarios.

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  • Understanding of Newton's laws of motion
  • Knowledge of static and kinetic friction coefficients
  • Basic principles of equilibrium in mechanics
  • Familiarity with pulley systems and tension forces
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  • Study the calculations for static friction using the formula F_friction = µ_static * N
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blocks A and B have weights of 45 N and 25 N, respectively.



block A is sitting on a table and block B is attached to block A by a piece of string on a frictionless pulley and block B is hanging off the table. also block C is on top of block A



Figure 6-48
(a) Determine the minimum weight of block C to keep A from sliding if µstat between A and the table is 0.20.

(b) Block C suddenly is lifted off A. What is the acceleration of block A if µkin between A and the table is 0.15?
2 m/s2




A)
block a = 45n
block b = 25n
block c = 45 -25
block C = 20N i don't think this is right

B) can't solve without part A
 
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Find out the forces acting on A and C. Similarly find out the force acting on B. Find the acceleration of the system. Find the condition for the equilibrium.
 

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