How Much Wire Should Be Laid Underwater to Minimize Cost?

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Homework Help Overview

The problem involves determining the optimal length of wire to be laid underwater versus above ground to minimize costs for a new cottage located across a river from a telephone relay station. The river is 120 meters wide, and the cost of laying wire differs based on whether it is underwater or above ground.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of the cost function based on the distances involved and the costs associated with each type of wire laying. There are attempts to differentiate the cost function and find critical points, with some participants questioning the accuracy of their calculations and the interpretation of results.

Discussion Status

Some participants have provided guidance on checking calculations and clarifying the relationship between the variables involved. There is acknowledgment of potential errors in numerical input and the need for further calculations to arrive at the correct underwater distance.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information they can use or reference. There is an emphasis on ensuring the correct interpretation of the problem's requirements, particularly regarding the distances involved.

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Homework Statement


A new cottage is built across the river and 300 m downstream from the nearest telephone relay station. The river is 120m wide. In order to wire the cottage for phone service, wire will be laid across the river under water, and along the edge of the river above ground. The cost to lay wire under water is $15 per m and the cost to lay wire above ground is $10 per m. How much wire should be laid under water to minimize cost?


Homework Equations


a^2 + b^2 = c^2


The Attempt at a Solution


C = 15\sqrt{x^2+14400} + 10(300-x)
C' = 15 \cdot (\sqrt{x^2+14400})' - 10
= 15 \cdot \frac{1}{2\cdot\sqrt{x^2+14400}} \cdot(x^2+14400)' -10
= \frac{15\cdot (x^2)'} {2\cdot\sqrt{x^2+14400}} -10
= \frac{15\cdot2x}{2\cdot\sqrt{x^2+14400}} -10
= \frac{15x}{\sqrt{x^2+14400}} -10

I'm just wondering if someone can look this over and let me know where I'm going wrong? I proceeded to solve for f'(x) = 0 and I'm getting 10.7, so I know I'm doing something wrong.

I apologize for the use of ' for prime (this was how I was taught in the lesson).

Thank you very much for your time.
 
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Just double checking the numbers (your method looks fine), I get 107.3.

You might have typed in 1440 instead of 14400 in your calculator, which would explain the difference in exactly one order of magnitude.

Just note that this value is x, the distance not traveled above ground. The problem asks for the distance underwater so another calculation is needed after this.
 
Oh, okay, well then I guess it was actually the next part that I wasn't sure how to do!

My attempt from there was:
10 = \frac{15x}{\sqrt{x^2+14400}}
100 = \frac{15x}{x^2+14400}

I'm going to stop there for now in case I'm already making the mistake?
 
or if it's supposed to be
10\cdot\sqrt{x^2+14400} = 15x
 
You can keep it as a fraction, but when you square each side of the equation make sure to square the numerator i.e. 15x.

Your second post is another (easier imo) way of looking at the problem. From here you can divide both sides by 10 and then square the whole problem leaving you with:

14,400+x2= 9/4 x2

14,400= 5/4 x2

11,520= x2

107.3≈ x
 
Wow that's embarrassing.. thank you! I guess it's time for a break
 

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