How Much Work for a Chin-Up Based on Body Mass?

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SUMMARY

The discussion focuses on calculating the work done during a chin-up based on body mass, specifically addressing three parts of a homework problem. The work done per kilogram of body mass is determined using the formula Us = mgh, where 'h' is 0.40 m. Additionally, the discussion explores the percentage of muscle mass required to generate 70 J of work per kilogram for both the man and his son, emphasizing the relationship between muscle mass and work output.

PREREQUISITES
  • Understanding of physics concepts such as work, force, and gravitational potential energy.
  • Familiarity with the equations Us = mgh and W = Fd.
  • Basic knowledge of body composition and muscle mass percentages.
  • Ability to perform unit conversions and percentage calculations.
NEXT STEPS
  • Research the application of Us = mgh in different physical scenarios.
  • Explore the relationship between muscle mass and work output in various sports.
  • Learn about body composition analysis techniques and their implications for fitness.
  • Investigate the biomechanics of chin-ups and other bodyweight exercises.
USEFUL FOR

Students studying physics, fitness enthusiasts analyzing body mechanics, and anyone interested in the relationship between muscle mass and physical performance.

Chandasouk
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Homework Statement



While doing a chin-up, a man lifts his body 0.40 m.



Homework Equations



Us = mgh
W = Fd

a) How much work must the man do per kilogram of body mass?

b)The muscles involved in doing a chin-up can generate about 70 J of work per kilogram of muscle mass. If the man can just barely do a 0.40-m chin-up, what percentage of his body's mass do these muscles constitute? (For comparison, the total percentage of muscle in a typical 70-kg man with 14% body fat is about 43%.)

c)Repeat part (b) for the man's young son, who has arms half as long as his father's but whose muscles can also generate 70 J of work per kilogram of muscle mass.


I have no clue how to begin. It seems they only provided me with [tex]\Delta[/tex]X = .40m
 
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Hi Chandasouk! :smile:

(have a delta: ∆ :wink:)
Chandasouk said:
… I have no clue how to begin. It seems they only provided me with [tex]\Delta[/tex]X = .40m

Yes, they have … they've also provided you with the mass (because everything is per kilogram). :wink:
 

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