How Much Work is Done Moving a Charge in a Conducting Rod?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the work done in moving a charge across a conducting metal rod when there is a potential difference. The subject area includes concepts of electric potential and work in electrostatics.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the equation for work done in terms of electric potential and questions the sign of the work based on the direction of charge movement. Some participants suggest reconsidering the interpretation of the work done, particularly distinguishing between work done by the electric field and work done by an external force.

Discussion Status

Participants are exploring the nuances of the problem, particularly the assumptions underlying the question regarding the nature of the work being calculated. There is a recognition of the need for clarity in the question's intent, but no consensus has been reached on the interpretation.

Contextual Notes

The original poster notes a potential ambiguity in the question regarding whether it refers to the work done by the electric field or the work done by an external force, indicating a possible lack of specificity in the problem statement.

heynkm1
Messages
2
Reaction score
0
1.


If the electrical potential across a conducting metal rod of length L is V, how much work is done in moving a charge of +ne across the length of the rod, from low to high potential?


2.

Equation that I used: delta U = q * V



3.

This is what I thought: the charge moves from low to high potential, so the work done (by the electric field) has to be negative (so W = -neV). The answer was W = +neV.

Is my thought process incorrect, or should the question have been more specific and ask for exactly the work it was looking for (Work done by electric field or work done by external force)?
 
Physics news on Phys.org
Hi welcome to PF!

Think about what units the eqaution WD=V*q would have then look at the answer you gave us :D
 
heynkm1 said:
This is what I thought: the charge moves from low to high potential, so the work done (by the electric field) has to be negative (so W = -neV). The answer was W = +neV.

Is my thought process incorrect, or should the question have been more specific and ask for exactly the work it was looking for (Work done by electric field or work done by external force)?
The presumption (tacit, unfortunately) of the question is: What work would need to be done by you (an external force) to move the charge (not the work done by the field, when the charge is moved).
 
OK, thank you for your help.
 

Similar threads

Replies
12
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
Replies
4
Views
1K
Replies
1
Views
1K
Replies
4
Views
3K
Replies
4
Views
1K
Replies
11
Views
2K
Replies
14
Views
2K
Replies
5
Views
1K
  • · Replies 12 ·
Replies
12
Views
1K