How Much Work is Done When Separating Two Opposite Pole Magnets?

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SUMMARY

The discussion focuses on calculating the mechanical work done when separating two opposite pole magnets, specifically when the distance between them increases from 2 cm to 7 cm. The relevant equations include W=Fs for work and F=k1/x² for force, where k1 is a constant. The user attempted to solve the problem through integration, resulting in an expression that requires further clarification regarding the use of Boltzmann's constant in this context. The consensus suggests that Boltzmann's constant is not applicable to magnetic force calculations.

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Hello!

Homework Statement


This is a problem with magnetism and mechanical work.
Two magnets are facing each other with opposite poles, where the space between them is called x. The left magnet is beeing hold still, and the right magnet moved. The space between them increases from 2 to 7 cm. Estimate how much mechanical work this movement performs.

We do also have a table:

http://dump.no/files/b1c64a658d37/Table.jpg

Basically what's standing there is: "This table shows the relation between F and x"
Avstand=distance and kraft=force. (Norwegian)

Link to the picture if it doesn't show up in the thread:
http://dump.no/files/b1c64a658d37/Table.jpg


Homework Equations


[tex]W=Fs[/tex]

[tex]F=\frac{k1}{x^{2}}[/tex] Where k=Boltzmann's constant


The Attempt at a Solution


My attempt on this problem implies integration, because the force is not constant. I integrated [tex]F=\frac{k1}{x^{2}}[/tex] and got [tex]-\frac{1}{{x_B }} + \frac{1}{{x_A }}[/tex], where [tex]x_B[/tex]=2 and [tex]x_A[/tex]=7. I then get [tex]-\frac{5}{{14}}[/tex]. Am I supposed to multiply this with boltzmann's constant? And then put the result I found in the formula for work?


In advance, thanks for your help!
 
Last edited by a moderator:
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It looks right. But convert of distance from cm to m. I don't think Boltzmann's constant appears in the magnetic force.
 

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