How Much Work Is Required to Move a Refrigerator Across a Frictional Surface?

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SUMMARY

The discussion focuses on calculating the work required to move a 100 kg refrigerator across a frictional surface with a friction force of 200 N over a distance of 6 meters. The participant correctly applies the work-energy principle, concluding that the work done, W(K), is 1200 Joules. This calculation is validated by using the equation W(T) = -W(f) = f * Δl, confirming that the work needed to overcome friction is accurately determined.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the work-energy principle
  • Basic knowledge of frictional forces
  • Ability to perform calculations involving force and distance
NEXT STEPS
  • Study the work-energy theorem in detail
  • Explore different types of friction and their effects on motion
  • Learn about calculating work done against various forces
  • Investigate real-world applications of work calculations in physics
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of work calculations involving frictional forces.

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Homework Statement


A 100 kg refrigerator is on rest on the floor.How much work is needed to move the refrigerator at a constant speed for 6 m along with a floor friction force of 200 N ?


Homework Equations


I used ΔK = W(Fg)+ W (N) + W(f)+ W(T) =0
and W(Fg)+ W (N) = 0
so W(T)=-W(f)=f* Δl

The Attempt at a Solution



The needed work is W(K)= 1200 J

Is it correct ??
 
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Looks correct to me!
 

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