How Should Birthdays Be Counted for a Class of 60?

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Homework Help Overview

The discussion revolves around a probability problem concerning the counting of unique birthdays for a class of 60 students. Participants are exploring whether to use combinations or permutations to determine the number of ways students can have distinct birthdays, considering a year with 365 days.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the distinction between combinations and permutations, with some suggesting that the problem involves distinguishable students, which influences the choice of method. There is also a breakdown of how to approach the counting of unique birthdays based on the number of students.

Discussion Status

The discussion is active, with participants providing insights into the problem's requirements and clarifying the concepts of permutations and combinations. Some guidance has been offered regarding the appropriate mathematical approach, though no consensus has been reached on the final method to use.

Contextual Notes

There is mention of the specific case of February 29th, which introduces a potential complication regarding the total number of unique birthdays available, although this has not been fully explored in the discussion.

kirkulator
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I just started a probability course and I'm not sure if i should use a combination or permutation for this question:

How many ways are there that no two students will have the same birth date in a class size of 60?

Should i do 365C60 or 365P60?

Thanks so much!
-Amanda
 
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I would actually start from basics

pick the first student, can choose from 365 unique bdays,
the 2nd can choose from unique 364..
..
the 60 can choose from unique 365-59

so you get a total of
365*364*...*(365-59)

which does this look most like?
 
Then you should check what the question is exactly asking, can you assume the students are distinuigishable, which I think you can for this case
 
Yeah I should have thought about the distinguishable factor. combinations don't care about any particular order so they can have repeats of cases...as far as what I've learned about them...whereas permutations only count specific outcomes once [making the outcomes distinguishable] and yes, i see now that ishould use a permutation

i had written down
365!/(365-60)!
which is a permutation but i don't think i was clearly thinking about the difference between permutation and combination so i was afraid i was missing a factor in the denominator. this sounds right! thanks so much for the clarification! : )

by the way; next time ill write down what i have worked out so far in the original post.

-Amanda
 
Last edited:
kirkulator said:
I just started a probability course and I'm not sure if i should use a combination or permutation for this question:

How many ways are there that no two students will have the same birth date in a class size of 60?

Should i do 365C60 or 365P60?

Thanks so much!
-Amanda

Don't forget that a few million people were born on Feb 29th...

BBB
 

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