How Should Derivatives in Multivariable Chain Rules Be Notated?

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hojoon yang
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Hi

Equation: d/dz of f(x, 2z - x) = 2 * f(x, 2z - x), with x held fixed.


I understood above differential

## typo. RHS= 2*f ' (x,2z-x)

but, what is answer of below equation?

Handwritten-style expression: d/dz of f(g(z), 2z - x) = ?


is this right?

f ' ( g(z),2z-x) * g' (z) + f ' ( g(z),2z-x) *2
 
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hojoon yang said:
Hi

Handwritten-style equation: d/dz of f(x, 2z - x) equals 2 times f(x, 2z - x), with the derivative operator d/dz on the left side.


I understood above differential

## typo. RHS= 2*f ' (x,2z-x)
This notation is ambiguous, because it is not clear whether you differentiate ##f## w.r.t. the first or second variable. So I would write
$$
\frac{d}{dz} f(x, 2z - x) = 2 D_2f(x, 2z - x)
$$
instead. (There are other notations, but choose one that is clear.)
hojoon yang said:
but, what is answer of below equation?

Handwritten-style expression: d/dz of f(g(z), 2z - x) equals question mark, with the derivative operator d/dz on the left and the nested function arguments shown inside f.


is this right?

f ' ( g(z),2z-x) * g' (z) + f ' ( g(z),2z-x) *2
Same comment as above. Change the first ##f'## to ##D_1f## and the second ##f'## to ##D_2f##.
 
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