How Should Initial Conditions Be Applied in Solving Differential Equations?

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SUMMARY

The discussion focuses on solving the differential equation y''' - 6y'' + 8y' = 9e^x with initial conditions y(0) = 13, y'(0) = 17, and y''(0) = 16. The general solution for the homogeneous equation is derived as y = A0.5e^{2x} + B0.25e^{4x} + C. Participants confirm that initial conditions should not be applied until after finding the particular solution using the method of undetermined coefficients, which will be added to the general solution of the homogeneous equation.

PREREQUISITES
  • Understanding of differential equations, particularly third-order linear equations.
  • Familiarity with the method of undetermined coefficients for finding particular solutions.
  • Knowledge of homogeneous vs. nonhomogeneous equations.
  • Ability to apply initial conditions to solutions of differential equations.
NEXT STEPS
  • Study the method of undetermined coefficients in detail.
  • Learn about the characteristics of homogeneous and nonhomogeneous differential equations.
  • Practice applying initial conditions to general solutions of differential equations.
  • Explore advanced topics in differential equations, such as Laplace transforms.
USEFUL FOR

Mathematics students, educators, and professionals involved in solving differential equations, particularly those focusing on initial value problems in applied mathematics and engineering.

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y is a function of x if
[tex]y'''-6y''+8y'=9e^x[/tex]
[tex]y(0)=13, y'(0)=17, y''(0)=16[/tex]
solve for y(x)=

I first solved for [tex]y'''-6y''+8y'=0[/tex]
I got the general solution:
[tex]y=A0.5e^{2x}+B0.25e^{4x}+C[/tex]

I was just wondering if I should plug in the initial conditions now or should I solve the 9e^x and then solve for the initial conditions? Also, if I solved for 9e^x now, would the costant C just be zero?
 
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You don't solve for the initial conditions now, because the equation you got, [itex]y=Ae^{2x}+Be^{4x}+C[/itex] is the solution to the corresponding homogeneous equation only, and not the solution of the original nonhomogeneous equation given in the initial problem.

You can now find the particular solution of the nonhomogeneous equation by the method of undetermined coefficients.

The general solution of the nonhomogeneous equation will be the sum of the solution of the homogeneous equation and the particular solution of the nonhomogeneous equation. You should substitute your initial conditions to this general solution
 

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