How Small Can Accelerators Detect Particles?

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Homework Help Overview

The discussion revolves around the resolution limits of particle accelerators, specifically focusing on the wavelength of probing beams and their relation to the size of particles being detected. The original poster attempts to calculate the smallest resolvable size of objects using the momentum of alpha particles emitted during radioactive decay.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculations of momentum and wavelength, with the original poster initially arriving at an implausibly large momentum value. There are questions about the accuracy of the calculations and the interpretation of the size of electrons.

Discussion Status

Some participants have provided guidance on recalculating momentum and have pointed out errors in the original calculations. There is an ongoing exploration of the implications of the results, particularly regarding the size of electrons and the validity of the references used.

Contextual Notes

There are references to homework notes and external links that provide context for the size of particles, which are under scrutiny for their accuracy. The discussion reflects uncertainty about the definitions and measurements of particle sizes.

crybllrd
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Homework Statement


the wavelength of the probing beam must be approximately the same as the size of objects we want to resolve. For each of the accelerators described below, determine the smallest size objects that are resolvable and name an object roughly that small, remembering that these are order-of-magnitude estimates.
(a) In the radioactive decay of radium, most emitted [tex]\alpha[/tex]particles (4He nuclei) travel at 1.5 ×10^7 m/s. This is what was used in the Geiger-Marsden Experiment.
(there are actually four questions, but I am trying to make sure I am on the right track)

Homework Equations


p=[tex]\frac{mv}{\sqrt{1-\frac{v^{2}}{c^{2}}}}[/tex]

p=[tex]\frac{h}{\lambda}[/tex]

[tex]\lambda[/tex]=[tex]\frac{h}{p}[/tex]

where h = Planck's constant

The Attempt at a Solution



Sorry, I am not too good with LATEX references...

a) v= 1.5e7 m/s
m=6.64e-27 kg

p=[tex]\frac{(6.64e-27 kg)(1.5e7 m/s)}{\sqrt{1-\frac{(1.5e7 m/s)^{2}}{3e8m/s^{2}}}}[/tex]

I solve this equation to get momentum 9.97e20 kg*m/s, then plug it into the next formula to find the wavelength:
[tex]\lambda[/tex]=[tex]\frac{6.626 J*s}{9.97e20 kg*m/s}[/tex]

I get this answer:

[tex]\lambda[/tex]=6.65e-55

which is much smaller than an electron, quark or a string.

Surely I did something wrong, but I can't find my mistake.
 
Physics news on Phys.org
Redo the momentum calculation. Your value of order 1020 kg m/s is absurdly large for an alpha particle.

*** Additional comment on edit ***
Also your value of h is missing the appropriate powers of 10.
 
Last edited:
Thanks so much. I missed the math error, I didn't have the negative sign for the scientific notation.
I now have the answer of 6.65e-15m, which is about the size (as far as orders of magnitude go) of an electron.
That was the answer I was looking for!
Thanks again
 
Where does it say electrons are 10^-15 m across? Electrons, as far as we know, have 0 size. Experiments have certainly constrained its radius to no larger than 10^-18 m.
 
Note, that link actually says electrons are somewhere between 0 and 1e-15 meters.
 

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