SUMMARY
The problem involves calculating the height of a bridge based on the horizontal distance a rock travels when thrown horizontally. Given that the rock hits the water 30 meters away and is in the air for 2 seconds, the correct formula to use is d = 0.5 * g * t², where g is the acceleration due to gravity (9.8 m/s²). The calculation yields a height of 19.6 meters for the bridge, confirming that the initial assumption was correct. The confusion arises from misinterpreting the distance traveled in the first second versus the speed at that moment.
PREREQUISITES
- Understanding of projectile motion principles
- Familiarity with the equations of motion, specifically d = 0.5 * g * t²
- Knowledge of gravitational acceleration (9.8 m/s²)
- Basic algebra for solving equations
NEXT STEPS
- Study the concepts of vertical and horizontal motion in projectile motion
- Learn about the effects of air resistance on projectile trajectories
- Explore advanced projectile motion problems involving angles
- Investigate real-world applications of projectile motion in physics
USEFUL FOR
Students studying physics, educators teaching projectile motion, and anyone interested in understanding the dynamics of objects in motion.