A ball is thrown from a bridge 200 m high with an initial velocity of 34.4 m/s at an angle of 54° above the horizontal.
I'm not sure... arctan Vx/Vy = x? I really don't know.
The Attempt at a Solution
(a) How high above the throwing height does the ball go: 39.5 meters
(b) The total time the ball is in the air: 9.83 seconds
(c) The horizontal distance the ball travels before it hits the water: 199 meters
(d) The velocity of the ball as it strikes the water: 71.4 meters/second
And here is the one I don't know how to calculate.
Direction _______ degrees below the horizontal.
I know the answer to be 73.6 degrees, I do not know how to calculate the answer. I was looking for an online resource, but I could only find information under the assumption of a level field as opposed to launching the projectile from a height. I was able to fairly easily calculate the other numbers there, but ran into an issue trying ti figure out the last part.