How to Calculate Current from a Circuit Using Voltage Division Law?

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SUMMARY

The discussion focuses on calculating current in a circuit using the Voltage Division Law and Kirchhoff's laws. The user applies the voltage division formula to determine voltages across resistors, specifically using values of 0.04, 13, and 28 ohms. The equations derived from Kirchhoff's laws are utilized to solve for currents i1 and i2 in the circuit. The final equations established are critical for accurately determining the current flow in the circuit.

PREREQUISITES
  • Understanding of Voltage Division Law
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Basic circuit analysis techniques
  • Knowledge of Ohm's Law
NEXT STEPS
  • Study advanced applications of Voltage Division Law in complex circuits
  • Learn how to apply Kirchhoff's Current Law (KCL) in circuit analysis
  • Explore the use of circuit simulation software like LTspice for practical applications
  • Investigate the impact of resistor values on current distribution in parallel circuits
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Electrical engineering students, circuit designers, and anyone involved in circuit analysis and design will benefit from this discussion.

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Homework Statement



http://img638.imageshack.us/img638/2416/64523221.jpg

Homework Equations





The Attempt at a Solution



My approach at this problem is using the voltage division law:

I first need to find the voltage at the 12 ohm, this can be done by the following using voltage division law.

Vb = (0.04 * 13)/ 41
Va = (0.04 * 28)/ 41

then we subtract the two, is this true?
 
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Let i branch out. i1 flows in upper loop and i2 flows in the lover loop.
Apply Kirchhoff law.
For upper loop
-12i -17i1 = 0...(1)
For lower loop
-12i - 24 i2 = 0...(2)
Similarly write down the equation for the left side loop which contains the voltage source and solve the equations to find i.
 
is the left side equal to:

40mV - 28i = 0
 
-EquinoX- said:
is the left side equal to:

40mV - 28i = 0
No. i1 and i2 are in the opposite direction.
So it should be
40 mV = 16*i1 - 12*i2
 

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