How to Calculate Current in a Solenoid with Given Field and Dimensions?

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SUMMARY

The discussion focuses on calculating the current required in a solenoid to achieve a magnetic field of 0.215 T, given its dimensions and number of turns. The relevant formula used is B = μIN / l, where B is the magnetic field, μ is the permeability of free space, I is the current, N is the number of turns, and l is the length of the solenoid. For a solenoid measuring 27.0 cm in length with 900 turns, the necessary current can be determined without needing the diameter, which serves as extraneous information in this context.

PREREQUISITES
  • Understanding of the formula B = μIN / l
  • Knowledge of magnetic fields and solenoid properties
  • Familiarity with the concept of permeability of free space (μ)
  • Basic algebra for solving equations
NEXT STEPS
  • Calculate the current using the formula B = μIN / l with μ = 4π x 10^-7 T·m/A
  • Explore the effects of varying the number of turns (N) on the magnetic field strength
  • Investigate the relationship between solenoid dimensions and magnetic field intensity
  • Learn about applications of solenoids in electromagnetic devices
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Students studying electromagnetism, physics educators, and anyone interested in practical applications of solenoids in engineering and technology.

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Homework Statement



A 27.0-cm long solenoid 1.25 cm in diameter is to produce a field of 0.215 T at its center. How much current should the solenoid carry if it has 900 turns of the wire?

Homework Equations



B = μIN / l

The Attempt at a Solution



Why am I given the diameter plus the length? Everything else is obvious except this concept. I thought l would equal = 0.27 m. Should I add 0.625 + 0.27 m because the magnetic field is produced at the center?
 
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you don't need the diameter at all for this problem ;)
 
Aha! Extra information! Thank you.
 

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