MHB How to Calculate Distances from Foci to Tangent Line on an Ellipse?

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To calculate the distances from the foci of an ellipse to a tangent line, the distance formula involves the projection of the vector from a point on the ellipse to the point of tangency onto a normal vector of the tangent line. The tangent line can be expressed using the parametrization of the ellipse and its derivative. The normal vector is derived from the tangent line's direction, specifically using the coordinates related to the ellipse's parameters. Additionally, it is noted that the angles formed by lines connecting the foci to any point on the ellipse with the tangent line are equal. Understanding these geometric relationships is crucial for solving the exercise effectively.
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Hey! :o

I am looking at the following exercise:

Consider the ellipse $$\frac{x^2}{p^2}+\frac{y^2}{q^2}=1$$
where $p > q > 0$. The eccentricity of the ellipse is $\epsilon =\sqrt{1-\frac{q^2}{p^2}}$ and the points $(\pm \epsilon p, 0)$ on the $x$-axis are called the foci of the ellipse, which we denote by $f_1$ and $f_2$. Verify that $\gamma (t) = (p \cos t, q \sin t)$ is a parametrization of the ellipse. Prove that:
  1. The product of the distances from $f_1$ and $f_2$ to the tangent line at any point $p$ of the ellipse does not depend on $p$.
  2. If $p$ is any point on the ellipse, the line joining $f_1$ and $p$ and that joining $f_2$ and $p$ make equal angles with the tangent line to the ellipse at $p$.

Since $\gamma (t)=(p \cos t , q \sin t)$ we have that $\gamma '(t)=(-p\sin t, q\cos t)$.

The tangent line is given by $l(t)=\gamma (t_0)+t\gamma' (t_0)$.

How can we calculate the distances from $f_1$ and $f_2$ to the tangent line?

Could you give me some hints what we could do at the second question?
 
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mathmari said:
Since $\gamma (t)=(p \cos t , q \sin t)$ we have that $\gamma '(t)=(-p\sin t, q\cos t)$.

The tangent line is given by $l(t)=\gamma (t_0)+t\gamma' (t_0)$.

How can we calculate the distances from $f_1$ and $f_2$ to the tangent line?

Could you give me some hints what we could do at the second question?

Hi mathmari! (Wave)

The distance of a point $\mathbf F$ to a line $l$ through $\mathbf P$ in the direction $\mathbf d$, is given by:
$$d(\mathbf F, l) = ||\boldsymbol\pi_{\mathbf n}(\mathbf F-\mathbf P)|| = (\mathbf F-\mathbf P) \cdot \mathbf n$$
where $\boldsymbol\pi_{\mathbf n}$ is the projection on a normal $\mathbf n$ of the line (perpendicular to $\mathbf d$).
And that projection is given by the dot product if $\mathbf n$ is a vector of unit length.

In your case $\mathbf n$ is given by $(q\cos t, p\sin t)$.

For the second question I think you're supposed to use another application of the dot product.
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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