How to Calculate Electric Flux through a Pyramid's Slanted Surfaces?

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Homework Help Overview

The problem involves calculating the electric flux through the slanted surfaces of a pyramid placed in a vertical electric field. The pyramid has a square base measuring 6.00 m on each side and a height of 4.00 m, with the electric field strength given as 52.0 N/C.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the geometry of the pyramid and the relationship between the area vector of the surfaces and the electric field vector. There is mention of calculating the hypotenuse and the area of the sides, along with challenges in determining the angle between the vectors.

Discussion Status

Some participants are actively sharing their attempts and seeking clarification on specific aspects of the problem, such as the angle between vectors. Hints have been provided to consider the relationship between the flux through the slanted surfaces and the base of the pyramid.

Contextual Notes

Participants are encouraged to show their work and identify where they are encountering difficulties, indicating a collaborative approach to problem-solving.

shinobi12
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Homework Statement


A pyramid with horizontal square base, 6.00 m on each side, and a hieght of 4.00 m is placed in a vertical electric field of 52.0 N/C. Calculate the total electric flux through the pyramid's four slanted surfaces.


Homework Equations



Phi = E*A*cos(theta)

The Attempt at a Solution

 
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shinobi12 said:
A pyramid with horizontal square base, 6.00 m on each side, and a hieght of 4.00 m is placed in a vertical electric field of 52.0 N/C. Calculate the total electric flux through the pyramid's four slanted surfaces.

Hi shinobi12! :smile:

Show us what you've tried, and where you're stuck, and then we'll know how to help. :smile:
 
i found the length of the of the hypotenuse and found the area of the side and I am having trouble figuring out the angle of the area vector and the electric field vector
 
shinobi12 said:
i found the length of the of the hypotenuse and found the area of the side and I am having trouble figuring out the angle of the area vector and the electric field vector

Hint: what is the relationship between the flux through the four slanted surfaces, and the flux through the base? :wink:
 
think of flux as flowing water. what is the net flow of water through the walls of the pyramid?
 

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