How to Calculate Electric Flux through a Pyramid's Slanted Surfaces?

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shinobi12
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Homework Statement


A pyramid with horizontal square base, 6.00 m on each side, and a hieght of 4.00 m is placed in a vertical electric field of 52.0 N/C. Calculate the total electric flux through the pyramid's four slanted surfaces.


Homework Equations



Phi = E*A*cos(theta)

The Attempt at a Solution

 
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shinobi12 said:
A pyramid with horizontal square base, 6.00 m on each side, and a hieght of 4.00 m is placed in a vertical electric field of 52.0 N/C. Calculate the total electric flux through the pyramid's four slanted surfaces.

Hi shinobi12! :smile:

Show us what you've tried, and where you're stuck, and then we'll know how to help. :smile:
 
i found the length of the of the hypotenuse and found the area of the side and I am having trouble figuring out the angle of the area vector and the electric field vector
 
shinobi12 said:
i found the length of the of the hypotenuse and found the area of the side and I am having trouble figuring out the angle of the area vector and the electric field vector

Hint: what is the relationship between the flux through the four slanted surfaces, and the flux through the base? :wink:
 
think of flux as flowing water. what is the net flow of water through the walls of the pyramid?