How to Calculate Equilibrium Pressures in a Chemical Reaction?

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The discussion focuses on calculating equilibrium pressures for the reaction A + B → 2C, given initial pressures of Pa = 3 atm and Pb = 2 atm. It is established that 70% of B has reacted, leading to a change in pressures represented as -x for A and B, and +2x for C. The equilibrium pressures can be calculated as Pa = 3 - 0.7(2) = 2.6 atm, Pb = 2 - 0.7(2) = 0.6 atm, and Pc = 0 + 2(0.7) = 1.4 atm. The equilibrium constant can then be determined using these pressures.

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Reacton between the substances is A+B--> 2C where Pa=3 atm,Pb=2 atm.The reaction moves to the right until 70 percent of B has reacted and we have the equilibrum.FFind Pa,Pb,Pc and the constant of equilibrum

Pa Pb Pc

So in the beginning 3 2 0

The change - x -x +2x How do I find Pa ,Pb and Pc here?
 
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Elaia06 said:
Reacton between the substances is A+B--> 2C where Pa=3 atm,Pb=2 atm.The reaction moves to the right until 70 percent of B has reacted and we have the equilibrum.FFind Pa,Pb,Pc and the constant of equilibrum

Pa Pb Pc

So in the beginning 3 2 0

The change - x -x +2x How do I find Pa ,Pb and Pc here?

You are told that 70% of B has reacted...
 

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