How to Calculate Flow Rate in a Tapered Pipe with Pressure Difference?

[12342]

Homework Statement

An alcohol flows smoothly through a horizontal pipe that tapers in cross-sectional area from A1 = 43.7 cm2 to A2= A1/4. The pressure difference Δp between the wide and the narrow sections of the pipe is 8.8 kPa. What is the volume flow rate ΔV/Δt of the alcohol? The density of the alcohol is ρ = 796 kg/m3.

Homework Equations

I figured I would have to use:

v1 = sqrt( 2*deltap / 15(rho) )

The Attempt at a Solution

I'm not entirely sure how to start this. I'm very cinfused.

v^2

 

[rl.bhat]

Hi 12342, welcome to PF.
The relevant equations are
P1 +1/2*ρ*v1^2 = P1 + 1/2*ρ*v2^2 ...(1)
And rat of flow
Q = A1*v1 = A2*v2...(2)
From the second equation find v2 in terms of v1 and put it in eq. 1. Then solve for v1and then Q.