How to Calculate Flow Rate in a Tapered Pipe with Pressure Difference?

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SUMMARY

The discussion focuses on calculating the volume flow rate of alcohol in a tapered pipe, specifically transitioning from a cross-sectional area of A1 = 43.7 cm² to A2 = A1/4 with a pressure difference (Δp) of 8.8 kPa. The density of the alcohol is given as ρ = 796 kg/m³. Key equations utilized include Bernoulli's equation and the continuity equation, which relate pressure, velocity, and cross-sectional area. The solution involves deriving the velocity in the narrow section of the pipe and subsequently calculating the flow rate (Q).

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Homework Statement


An alcohol flows smoothly through a horizontal pipe that tapers in cross-sectional area from A1 = 43.7 cm2 to A2= A1/4. The pressure difference Δp between the wide and the narrow sections of the pipe is 8.8 kPa. What is the volume flow rate ΔV/Δt of the alcohol? The density of the alcohol is ρ = 796 kg/m3.


Homework Equations


I figured I would have to use:

v1 = sqrt( 2*deltap / 15(rho) )


The Attempt at a Solution



I'm not entirely sure how to start this. I'm very cinfused.

v^2
 
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Hi 12342, welcome to PF.
The relevant equations are
P1 +1/2*ρ*v1^2 = P1 + 1/2*ρ*v2^2 ...(1)
And rat of flow
Q = A1*v1 = A2*v2...(2)
From the second equation find v2 in terms of v1 and put it in eq. 1. Then solve for v1and then Q.
 

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