How to Calculate Force Between Moving Charged Particles?

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Homework Help Overview

The discussion revolves around calculating the force between two moving charged particles, specifically using the Lorentz force law in a relativistic context. The problem involves understanding the interactions between the particles as they move parallel to the x-axis with a given velocity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the use of Lorentz transformations to analyze the problem from a different frame of reference. There are discussions about the Coulomb force and the electric field generated by moving charges, with attempts to derive relevant equations.

Discussion Status

Participants are actively engaging with the problem, sharing equations and expressing uncertainty about their approaches. Some have provided equations related to the electric and magnetic fields of moving charges, while others are questioning whether they are on the right track.

Contextual Notes

There appears to be a need for clarification on the Lorentz force law and its application in this scenario. Participants are also navigating the complexities of relativistic effects on electric and magnetic fields.

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Homework Statement


In a frame S, two identical particles with electric charge q move abreast along lines parallel to the x-axis, a distance r apart and with velocity v. Determine the force in S that each exerts on the other, by use of the force law for a uniformly moving charge.



I would need a lorentz forc e law in 4 vector notation,

what is it? Then where do I proceed?


Homework Equations





The Attempt at a Solution

 
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My first thought would be to make a Lorentz transformation into the frame where both particles are at rest.
 
We know its just the Coulomb force,

we have the equation for field of a moving charge:

[tex] e= \frac{Q \bf{r_o}}{\gamma^2 r_o^2 (1-u^2/c^2 sin^2(\theta))^{3/2}}[/tex]

and we can determine the magnetic field in this case,
[tex] cb = \frac{\bf{v} \times \bf{e}}{c}[/tex]

I'm not sure at this point
 
Last edited:
The above equation was obtained by this:

[tex] \bf{e} = \frac{Q}{(cr-\bf{r}\bf{u})^3}\frac{c^2}{\gamma^2}(c\bf{r}-r\bf{u})[/tex]

I'm not sure of I"m on the right track.
 

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