How to Calculate Gauge Pressure to Compress Water?

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The discussion focuses on calculating gauge pressure needed to compress pure water from 1.000 L to 989 mL, requiring answers in both N/m² and psi. The calculations involve using the bulk modulus of water, which is 2.2 x 109 N/m². Additionally, the discussion includes determining the height of a steel bar needed to exert this pressure and the total weight of steel required for the task.

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predentalgirl1
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I have tried and tried to figure this out but I'm getting no where. Can anyone help me?

(a) Calculate the gauge pressure (it does not include atmosphereric P) required to compress pure water from 1.000 L to 989 mL. Give an answer in both N/m^2 and psi, lb/in^2.

(b) What height in meters and feet of a 1x1 cm^2 steel bar (density=7.86 g/cm^3) is required to exert the pressure found in part (a)?


(c) How many total pounds of steel would be required to exert this pressure on one cubic face of a liter of water (1 L= 1 cubic decimeter)?
 
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a. Use the formula for bulk modulus. B = delta P/(delta v)/v. B for water is 2.2*10^9 N/m^2.

I hope the other answers will follow.
 

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