- #1

Eddard

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Hey... I need help on a question i know how to calculate the decceleration of the truck in the problem below but I am not completely sure about how you would be able to find the conclusion to this question? Help would be appreiated

A 920 kg car is 65m from a concrete barrier traveling at 125 km/h, when the driver notices and slams on the breaks. The fritional force acting on the car is 8600N. Is the driver able to stop the car in time?

so this is what i got:M= 920kg

D=65m

V1=125 km/h

F(friction)=8600N

A=?

v1=0

F(net)=ma

-F(friction)=ma

A=-F(fric..)

=-0.935 m/s ^2V2^2=V1^2 + 2a*∆d

Rearranged the equation:

∆d= V2^2/2a∆d - square of V1

Then when i sub in the numbers and solve the equation I conclude that the car stops 2.11 meters away from the concrete barrier...but I am not sure if i did this right and if any part of this equation doesn't make sense ill try to explain...

A 920 kg car is 65m from a concrete barrier traveling at 125 km/h, when the driver notices and slams on the breaks. The fritional force acting on the car is 8600N. Is the driver able to stop the car in time?

so this is what i got:M= 920kg

D=65m

V1=125 km/h

F(friction)=8600N

A=?

v1=0

F(net)=ma

-F(friction)=ma

A=-F(fric..)

=-0.935 m/s ^2V2^2=V1^2 + 2a*∆d

Rearranged the equation:

∆d= V2^2/2a∆d - square of V1

Then when i sub in the numbers and solve the equation I conclude that the car stops 2.11 meters away from the concrete barrier...but I am not sure if i did this right and if any part of this equation doesn't make sense ill try to explain...

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