How to Calculate Initial Molarity of S2O32- in a Trial

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SUMMARY

The discussion focuses on calculating the initial molarity of thiosulfate ions (S2O32-) in a solution derived from 1.00 mL of 0.010 M sodium thiosulfate (Na2S2O3) diluted to a total volume of 7.00 mL. Participants emphasize using the dilution equation M1V1 = M2V2 to determine the molarity of S2O32- in each trial. The key calculation involves recognizing that the total moles of Na2S2O3 in the initial solution can be used to find the molarity in the final diluted solution. The correct approach leads to a molarity of approximately 0.00214 M for S2O32-.

PREREQUISITES
  • Understanding of molarity and dilution concepts
  • Familiarity with the equation M1V1 = M2V2
  • Basic knowledge of stoichiometry
  • Ability to convert grams to moles using molar mass
NEXT STEPS
  • Review the concept of dilution and its applications in chemistry
  • Practice calculations involving molarity using different concentrations and volumes
  • Learn about stoichiometric conversions and their importance in chemical reactions
  • Explore the properties and applications of sodium thiosulfate in various chemical processes
USEFUL FOR

Chemistry students, educators, and anyone involved in laboratory work requiring molarity calculations and solution preparation.

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Homework Statement


Calculate the initial molarity of S2O32- in each trial given that each trial has 1.00 mL of .010 M Na2S2O3 and a total volume of 7.00 mL.


Homework Equations


mol = g/(g/mol)
M1V1=M2V2

The Attempt at a Solution


(1)(.01)=7x
.0014=x
 
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Keep trying.
 


Hmm. Well that's really not that helpful to me. Do you have a hint on what I should do? I mean, I wouldn't be asking on this forum if I wasn't in need of help.
 


Can anyone help me out with this? I'm stuck.
 


Easier to use the definition of molarity. How many moles compound in each trial? How much volume of finished solution in each trial? Calculate the ratio.
 


symbolipoint said:
How many moles compound in each trial? How much volume of finished solution in each trial? Calculate the ratio.

It does not give the number of moles per trial. The question written above is all the information given.

The total volume is 7.00 mL. Is that how much volume of finished solution would be in each trial?
 


The total volume is 7.00 mL. Is that how much volume of finished solution would be in each trial?

Yes.
 


I'm still struggling.
I've calculated the grams of Na2S2O3 = 1.58 g, but I'm still confused as to how I get the molarity of S2O3
 


TypeFun said:
I'm still struggling.
I've calculated the grams of Na2S2O3 = 1.58 g, but I'm still confused as to how I get the molarity of S2O3

You have the molarity of the stock solution. You have the volume of a trial. These are enough to calculate molarity of a trial.
 

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