How to Calculate Magnetic Moment of Rotating Electrons in a Straight Line?

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Homework Help Overview

The discussion revolves around calculating the magnetic moment of two electrons rotating around the z-axis with a specific angular speed and phase difference. The problem involves concepts from electromagnetism and the application of different unit systems, specifically CGS and SI units.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the derivation of the magnetic moment using different equations and unit systems. Questions arise regarding the presence of the constant 'c' in the formula and its implications based on the chosen unit system. Comparisons are made to the magnetic moment of a single electron.

Discussion Status

The discussion is active with participants questioning the validity of the original poster's calculations and assumptions. Some have provided links to external resources for further verification, while others emphasize the importance of comparing results across different unit systems. There is no explicit consensus on the correctness of the initial approach.

Contextual Notes

Participants note the differences in results when using CGS versus SI units, highlighting the need for clarity in unit application. The original poster's reliance on a specific formula from class is also mentioned, indicating a potential constraint in their reasoning.

Maximtopsecret
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Homework Statement


Here we have two electrons rotating around z axis with angular speed w in a circle of radius R. They are on the same straight line (have difference in phase π). Find the magnetic moment.

Homework Equations


Magn. moment m=(1/2c)*∫dV [ r j ]

The Attempt at a Solution


Current J=dq/dt=qw/π;
m=(qw/2cπ)*∫dr∫dφ r*r*δ(r-R)=qwR2/c
Am I right?
 
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Is there a way you can verify this?
i.e. have you compared this answer with the magnetic moment for just one electron, same circle and speed?
 
Oh yes, I looked up a similar problem with 1 electron. There J=q/T; therefore m=0.5qwR2
What about 1/c? Is it referred to the fact that I used CGS system of units?
 
You should certainly compare like to like.
Where does the c come from in the derivation?

You can also check:
http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/magmom.html
... and derive the equation for a charge q going in a circle radius R.
Note: the current I is the amount of charge passing a point on the circuit every second.
 
Simon Bridge said:
You should certainly compare like to like.
Where does the c come from in the derivation?

You can also check:
http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/magmom.html
... and derive the equation for a charge q going in a circle radius R.
Note: the current I is the amount of charge passing a point on the circuit every second.

Yes, I checked your link above. From their formula m=I*S it follow for 2 electrons m=qwR2 - no 1/c. This result corresponds to the result of 1 electron.
But initially I tried to apply the general formula for m=(1/2c)*∫dV [r*j]; this formula was used in class where all tasks were done using CGS units.
So, I would stick to my opinion that 1/2c comes from CGS...
 
Maximtopsecret said:

Homework Statement


Here we have two electrons rotating around z axis with angular speed w in a circle of radius R. They are on the same straight line (have difference in phase π). Find the magnetic moment.

Homework Equations


Magn. moment m=(1/2c)*∫dV [ r j ]

The Attempt at a Solution


Current J=dq/dt=qw/π;
m=(qw/2cπ)*∫dr∫dφ r*r*δ(r-R)=qwR2/c
Am I right?
Maximtopsecret said:

Homework Statement


Here we have two electrons rotating around z axis with angular speed w in a circle of radius R. They are on the same straight line (have difference in phase π). Find the magnetic moment.

Homework Equations


Magn. moment m=(1/2c)*∫dV [ r j ]

The Attempt at a Solution


Current J=dq/dt=qw/π;
m=(qw/2cπ)*∫dr∫dφ r*r*δ(r-R)=qwR2/c
Am I right?
In SE units the c in the denominator would not be there. You on cgs or ?

Nice fancy equation but you could have just said m = IA, I = current, A = area.
 
rude man said:
In SE units the c in the denominator would not be there. You on cgs or ?

Nice fancy equation but you could have just said m = IA, I = current, A = area.
Yes, I do use CGS here.
 
Maximtopsecret said:
Yes, I do use CGS here.
As real physicists do! (I'm not one of them, I'm afraid) :frown:
(I meant SI of course, not SE).
rm
 

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