How to Calculate Mass in a Binary System with Given Orbital Period and Radius?

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SUMMARY

This discussion focuses on calculating the mass in a binary system using the orbital period and radius. The user attempts to derive the radius and mass using the equation (2∏/T)² = G*(ma + mb)/(ra + rb)³, simplifying it under the assumption that ma is significantly greater than mb. The user correctly identifies the orbital period as 2.8 years and calculates the circumference of the orbit, leading to a radius of approximately 2.1x10²² m. The discussion concludes with a clarification on neglecting ra relative to rb, confirming the approach taken is valid.

PREREQUISITES
  • Understanding of Kepler's laws of planetary motion
  • Familiarity with Newton's law of gravitation
  • Knowledge of orbital mechanics
  • Basic algebra for rearranging equations
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Astronomy students, astrophysicists, and anyone interested in understanding binary star systems and their mass calculations.

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Homework Statement



See attachment.

Homework Equations





The Attempt at a Solution



Ok, so for Qd) my attempt was:
d = vt = 75x10^3 * (2*2.8*86400*365) = 1.32x10^13 m, (circumference of orbit)
because the star periodically shifts from red to blue shifted frequencies every 2.8 years so I guess the full orbit to be 2*2.8 years.

Then 2∏r = 1.32x10^13, -> r = 2.1x10^12m?

Now for Qe) All I could figure is that the relevant eqn is (2∏/T)2 = G*(ma + mb)/(ra + rb)3

But with the information I have, 1stly from the assumpt that ma >> mb I can say that:

(2∏/T)2 = G*(ma)/(ra + rb)3 right?

Considering X-major is ma. Now I can rearrange for the mass but I still have missing information, I just have radius of the orbit for x-minor, but not x-major. I even have the orbital period. Just not ra.

Can someone give me a helping hand here, how do I find ra? Also have I done everything thus far correctly?
 

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Your work looks correct to me.

Under the assumption that ma >> mb, you have ra << rb. So, I think you can safely neglect ra relative to rb.
 
Lol that does make sense, silly me, thanks. Hopefully that's correct. :)
 

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