SUMMARY
The discussion focuses on calculating the number of moles of nitrogen in the compound C7H5(NO2)3 based on the oxygen content derived from 12.6 grams of sucrose (sugar). The correct approach involves first determining the moles of oxygen in sucrose by using the molar mass of sucrose (approximately 342 g/mol) and then equating it to the moles of oxygen in C7H5(NO2)3, which has three nitrogen atoms per molecule. The final calculation shows that the moles of nitrogen are derived from the mass of the compound, leading to a result of 15.3 grams of C7H5(NO2)3 for the equivalent moles of nitrogen.
PREREQUISITES
- Understanding of mole calculations in chemistry
- Knowledge of molar mass for common compounds, specifically sucrose (342 g/mol)
- Familiarity with Avogadro's number for converting moles to atoms
- Basic algebra for equating and solving equations
NEXT STEPS
- Study the concept of mole calculations in more detail, focusing on conversions between grams and moles
- Learn about the molecular structure and composition of C7H5(NO2)3
- Research the properties and molar mass of various sugars, particularly sucrose
- Explore stoichiometry in chemical reactions to understand relationships between reactants and products
USEFUL FOR
Chemistry students, educators, and anyone involved in chemical calculations, particularly those focusing on stoichiometry and molecular composition.