How to Calculate Moles of Nitrogen in C7H5(NO2)3 from Oxygen in 12.6g of Sugar?

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SUMMARY

The discussion focuses on calculating the number of moles of nitrogen in the compound C7H5(NO2)3 based on the oxygen content derived from 12.6 grams of sucrose (sugar). The correct approach involves first determining the moles of oxygen in sucrose by using the molar mass of sucrose (approximately 342 g/mol) and then equating it to the moles of oxygen in C7H5(NO2)3, which has three nitrogen atoms per molecule. The final calculation shows that the moles of nitrogen are derived from the mass of the compound, leading to a result of 15.3 grams of C7H5(NO2)3 for the equivalent moles of nitrogen.

PREREQUISITES
  • Understanding of mole calculations in chemistry
  • Knowledge of molar mass for common compounds, specifically sucrose (342 g/mol)
  • Familiarity with Avogadro's number for converting moles to atoms
  • Basic algebra for equating and solving equations
NEXT STEPS
  • Study the concept of mole calculations in more detail, focusing on conversions between grams and moles
  • Learn about the molecular structure and composition of C7H5(NO2)3
  • Research the properties and molar mass of various sugars, particularly sucrose
  • Explore stoichiometry in chemical reactions to understand relationships between reactants and products
USEFUL FOR

Chemistry students, educators, and anyone involved in chemical calculations, particularly those focusing on stoichiometry and molecular composition.

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Homework Statement



Determine the number of moles of Nitrogen atoms in a sample of C7H5(NO2)3 that has the same number of oxygen atoms as 12.6 grams of sugar.

Homework Equations


Mole calculations

The Attempt at a Solution



First find the amount of moles of Oxygen in sugar. Multiply 12.6g by 96grams O/ 180grams sugar to get 6.72grams of sugar. The divide 6.72grams by 16 to get 0.42 moles of Oxygen. Then I'm struggling at the next part. To get the same amount of moles of Nitrogen shouldn't I just divide 0.42 by 3 to get 0.14? 0.14 was not the correct response on mastering chem.
 
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Determine the number of moles of Nitrogen atoms in a sample of C7H5(NO2)3 that has the same number of oxygen atoms as 12.6 grams of sugar.


First calculate the no. of oxygen atoms in sugar
moles of sugar = 12.6/342
no. of O atoms= 12.6/342 x 11x N where N is avogadro number


Let the mass of the compound given be m
moles of this compound= m/227
no of O atoms= 6 x m/227 x N

equate and get m,
I got it as 15.3 g
Now moles of nitrogen atoms = 15.3/227 x 3
 
Isn't the molar mass of sugar 180 g/mole not 342?
 
What sugar? Ribose? Arabinose? Xylose? Gulose? Lyxose? Psicose? Fructose? Sorbose? Tagatose? Allose? Altrose? Glucose? Mannose? Idose? Galactose? Talose? Sucrose? Lactose? Maltose? Trehalose? Turanose? Cellobiose? Ribulose?
 
My bad, I meant glucose. Thanks for showing the steps to solving the problem.
 
Here in this question 'sugar' can be assumed as sucrose as nothing is mentioned about it.
 

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