How to Calculate Moles of Nitrogen in C7H5(NO2)3 from Oxygen in 12.6g of Sugar?

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Discussion Overview

The discussion revolves around calculating the number of moles of nitrogen atoms in the compound C7H5(NO2)3 based on the number of oxygen atoms present in 12.6 grams of sugar. The scope includes homework-related calculations and mole conversions.

Discussion Character

  • Homework-related, Mathematical reasoning, Debate/contested

Main Points Raised

  • One participant calculates the moles of oxygen in sugar using a conversion factor, arriving at 0.42 moles of oxygen, and suggests dividing this by 3 to find the moles of nitrogen, but questions the correctness of this approach.
  • Another participant proposes a different method, calculating the moles of sugar and then determining the number of oxygen atoms, ultimately suggesting a mass of 15.3 grams for the compound to equate the number of oxygen atoms.
  • A participant questions the molar mass used for sugar, suggesting it should be 180 g/mole instead of 342 g/mole.
  • Another participant raises the issue of which type of sugar is being referenced, listing various sugars to clarify the ambiguity.
  • A later reply clarifies that glucose was intended, acknowledging the previous confusion.
  • One participant suggests that 'sugar' can be assumed to be sucrose in the absence of specification.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the molar mass of sugar or the correct approach to the problem, indicating multiple competing views and unresolved calculations.

Contextual Notes

There are limitations regarding the assumptions made about the type of sugar and the molar mass used in calculations, which remain unresolved.

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Homework Statement



Determine the number of moles of Nitrogen atoms in a sample of C7H5(NO2)3 that has the same number of oxygen atoms as 12.6 grams of sugar.

Homework Equations


Mole calculations

The Attempt at a Solution



First find the amount of moles of Oxygen in sugar. Multiply 12.6g by 96grams O/ 180grams sugar to get 6.72grams of sugar. The divide 6.72grams by 16 to get 0.42 moles of Oxygen. Then I'm struggling at the next part. To get the same amount of moles of Nitrogen shouldn't I just divide 0.42 by 3 to get 0.14? 0.14 was not the correct response on mastering chem.
 
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Determine the number of moles of Nitrogen atoms in a sample of C7H5(NO2)3 that has the same number of oxygen atoms as 12.6 grams of sugar.


First calculate the no. of oxygen atoms in sugar
moles of sugar = 12.6/342
no. of O atoms= 12.6/342 x 11x N where N is avogadro number


Let the mass of the compound given be m
moles of this compound= m/227
no of O atoms= 6 x m/227 x N

equate and get m,
I got it as 15.3 g
Now moles of nitrogen atoms = 15.3/227 x 3
 
Isn't the molar mass of sugar 180 g/mole not 342?
 
What sugar? Ribose? Arabinose? Xylose? Gulose? Lyxose? Psicose? Fructose? Sorbose? Tagatose? Allose? Altrose? Glucose? Mannose? Idose? Galactose? Talose? Sucrose? Lactose? Maltose? Trehalose? Turanose? Cellobiose? Ribulose?
 
My bad, I meant glucose. Thanks for showing the steps to solving the problem.
 
Here in this question 'sugar' can be assumed as sucrose as nothing is mentioned about it.
 

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