How Do You Calculate the Net Force in Physics Problems?

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To calculate the net force in physics problems involving multiple charges, one must use the formula F = k(q1q2)/r^2 for each pair of charges. The net force is found by superposing the individual forces acting on a charge, meaning you add the forces calculated from each interaction. In the example discussed, the correct approach involves calculating the forces between charge A and charges B and C separately, then summing these forces. The initial calculation was incorrect because it did not account for the contributions from both forces. Understanding this method is crucial for accurately determining the net force in such problems.
Kofyebs
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Homework Statement


Calculate the net force on A.[/B]
upload_2016-5-20_20-4-1.png

Homework Equations


F=k . (q1 q2)/r^2 , k=9 x 10^9 Nm^2/C^2[/B]

The Attempt at a Solution


(9*10^9 Nm^2/C^2)(1,4 x 10^-6C)(7,2 x 10^-6C) / 1,7mm^2
= 0,0313.
Could someone tell me what I am missing even if what i did is even correct.
Thanks[/B]
 
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That’s NOT how you do it!
You add:
F(B)=k (qA qB)/(AB)^2 and F(C)=k (qA qC)/(AC)^2
As I said before, you ’superpose
’ (add) these 2 forces.
Do you understand now?
 
Poster has been reminded not to do too much of the student's work for them...
F=(9*10^9 Nm^2/C^2)(1,6 x 10^-6C)(1,4 x 10^-6C) / 1,7mm^2+(9*10^9 Nm^2/C^2)(1,6 x 10^-6C)(7,2 x 10^-6C) / 3,4mm^2
 
Yes! I understand now. Thanks once again. you've saved me. ;)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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