How to Calculate Power Radiated by a Sound Source?

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Homework Help Overview

The discussion revolves around calculating the power radiated by a sound source, specifically a loudspeaker with a given intensity and area. The subject area includes concepts of sound intensity and power calculations.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the relationship between intensity, power, and area to find the power radiated. Some participants question the complexity of the problem, suggesting it may not require advanced physics reasoning.

Discussion Status

The discussion is ongoing, with some participants providing feedback on the nature of the problem. There is a suggestion that the original poster's approach may be overly simplistic, but no consensus has been reached regarding the correctness of the calculations.

Contextual Notes

Participants note that the problem may be considered trivial, which could affect the level of engagement and responses from others.

Amith2006
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Sir,
A loud speaker having a circular opening of diameter 20 cm is emitting sound waves uniformly. The intensity of sound at the opening is 0.2 milli watt/m^2. What is the power radiated by the source?
I solved it in the following way:
Intensity = power/Area
Here Area = (pi)R^2
= 3.14 x 0.01
= 0.0314 m^2
Power = 0.2 x 0.0314 milli watts
= 6.28 x 10^(-6) watts
Is it right?
 
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Sir,
Please respond.
 
Amith2006 said:
Sir,
Please respond.
Amith, No one is responding to this because it is trivial. You are saying:

A/B = x

And then asking:

Does A = Bx?

This is hardly advanced physics.

AM
 
I think what he is saying is:

Does A/B = x ? In other words, does A = bx ??
 

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