It is found that Poyntings vector gives(adsbygoogle = window.adsbygoogle || []).push({});

P = ExH = (mu_{0}q^{2}a^{2}sin^{2}(theta)/6pi^{2}cr^{2})r

This apparently leads to

Total Power = (mu_{0}q^{2}a^{2}/6pi^{2}c)[tex]\int[/tex](sin^{2}(theta)/r^{2})(2pir^{2}sin(theta)d[tex]\theta[/tex])

What I am unsure of is where the

(2pir^{2}sin(theta)d[tex]\theta[/tex])

appears from. Can anyone help?

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# Power radiated by point charge Calculus

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