How Much Energy Hits Each Eardrum from a 2500W Sound Source 20m Away?

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SUMMARY

The energy hitting each eardrum from a 2500W sound source located 20 meters away is calculated using the intensity formula I=P/(4πr^2). The correct intensity at this distance is 0.497W/m², leading to an energy impact of 5.5*10^-5W on the eardrum, which has a surface area of 55mm². The discrepancy in the initial calculation arose from not accounting for the sound spreading over a hemisphere rather than a full sphere. This highlights the importance of understanding sound propagation in physics problems.

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Homework Statement


Standing 20m away from a tower generating 2500W of power how much energy/s hits each of your eardrums?
Surface area of eardrum=55mm^2
Assume that the speaker generates sound uniformly in a forward hemisphere.

Homework Equations


I=P/(4πr^2)
r=20m
P=2500W


The Attempt at a Solution


I=2500/(4π*20^2)=0.497W/m^2
Surface area of eardrum=55mm^2=55*10^-6m^2
0.497W/m^2*(55*10^-6)m^2=2.7*10^-5W
The actual answer is 5.5*10^-5W, not sure what went wrong.
 
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Note that the sound spreads over a hemisphere (not a sphere).
 
TSny said:
Note that the sound spreads over a hemisphere (not a sphere).
Oh that's sneaky, I'll have to pay more attention to that stuff in the future.
 

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