How to Calculate Projectile Motion with Initial Horizontal Velocity

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SUMMARY

The discussion focuses on calculating projectile motion for a car pushed horizontally off a 45m high cliff at an initial velocity of 2.0 m/s. The correct time to hit the ground is determined to be 3.0 seconds, while the horizontal distance traveled before landing is 6.0 meters. The participant initially misapplied the equation for vertical motion by confusing horizontal speed with vertical acceleration, which led to incorrect calculations. Clarification was provided on the separation of horizontal and vertical components in projectile motion.

PREREQUISITES
  • Understanding of basic physics concepts, specifically projectile motion.
  • Familiarity with kinematic equations, particularly s = ut + 0.5at².
  • Knowledge of gravitational acceleration, specifically g = 10 m/s².
  • Ability to differentiate between horizontal and vertical motion components.
NEXT STEPS
  • Study the principles of projectile motion in detail.
  • Learn how to apply kinematic equations to both horizontal and vertical motions separately.
  • Explore the effects of varying initial velocities on projectile trajectories.
  • Investigate real-world applications of projectile motion in engineering and physics.
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding the principles of projectile motion and its calculations.

Kotune
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Homework Statement


A night somebody pushes a derelict car horizontally off a 45m high cliff top at 2.0 ms^-1.
(a) How long does it take to hit the ground? (g=10ms^-2)
(b) How far from the base of the cliff does it land?


Homework Equations


The answer to (a) is 3.0s and (b) is 6.0m


The Attempt at a Solution


For (a) I tried s = ut +.5at^2. Hence 45 = 2t+.5(10)t^2 but the answer was not correct.
 
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Kotune said:
For (a) I tried s = ut +.5at^2. Hence 45 = 2t+.5(10)t^2 but the answer was not correct.

That's because you mixed a horizontal speed with a vertical acceleration.
 
Nugatory said:
That's because you mixed a horizontal speed with a vertical acceleration.

Ah ok I got it now, thanks :).
 

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