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How to Calculate the Arc Length of x^1/2

  1. Jun 29, 2011 #1
    So sorry if this has been discussed elsewhere before. I know it may be trivial but for some reason I just can't get it. I simply can't seem to integrate the square root of (1 + 1/4x). This problem has been highlighted for a reason, but I'm missing the point. Any input is much appreciated.
     
  2. jcsd
  3. Jun 29, 2011 #2
    Hi andryd9! :smile:

    What about a substitution

    [tex]u=\sqrt{1+\frac{1}{4x}}[/tex]
     
  4. Jun 29, 2011 #3
    Alternatively, you might want to calculate the arc length of x2. It should have the same value!
     
  5. Jun 29, 2011 #4
    Thank you for the help:)
     
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