How to calculate the dipole moment of the spherical shell?

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SUMMARY

The dipole moment of a spherical shell with a surface charge distribution of σ = k sinφ can be calculated using the integral P = ∫r' σ(r') da'. The dipole is oriented along the y-axis due to the nature of the sinφ function, which is positive from 0 to π and negative from π to 2π. The surface area element in spherical coordinates is given by da' = r² sinθ dθ dφ. The confusion arises from the application of the prime system and the spherical coordinates, leading to a misunderstanding of how to compute the three necessary integrals for the dipole moment vector.

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  • Understanding of spherical coordinates in physics
  • Knowledge of vector calculus and integration techniques
  • Familiarity with the concept of dipole moments
  • Experience with surface charge distributions
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Homework Statement


A spherical shell of radius R has a surface charge distribution σ = k sinφ.
Calculate the dipole moment of the spherical shell.

Homework Equations


P[/B]' = ∫r' σ(r') da'

The Attempt at a Solution


So I believe my dipole will be directed along the y axis, as the function sinφ is positive in the region 0-π and negative in π-2π. Dipoles point from negative to positive, so the right hand side of my sphere will be positive and left negative.

I also know that da' in spherical co-ordinates is r2 sinθdθdφ.

I also thought that maybe because I know my dipole is in y direction, I can do r' → y → rsinθsinφ. I saw another similar problem where the dipole was orientated in z, and they did r' → z → rcosθ.

However no matter what I do, zero seems to fall out at the end. I feel like my understanding of the whole prime system, or spherical co-ordinates, is maybe confused or I am misunderstanding the affect that the direction of the dipole has on this.

What am I doing wrong?
 
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Remember that dipole moment is a vector. So px = ∫x' σ(r') dA' and so on for y' and z'. There are three integrals to do.
 

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