amukher
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The energy emitted by a body in watts/m2 is = εσT4. In the case of a perfect black body, ε=1. If the body only emits IR light, what should be the value of ε?
The energy emitted through infrared (IR) waves can be calculated using the formula εσT4, where ε represents emissivity, σ is the Stefan-Boltzmann constant, and T is the absolute temperature in Kelvin. For a perfect black body, ε equals 1, but real bodies exhibit varying emissivities based on material and surface characteristics. Emissivity values range from 0 to 1 and are defined as the ratio of the spectral radiance of the body to that of a black body at the same temperature. Understanding these principles is crucial for accurately calculating thermal radiation, especially in contexts where only IR wavelengths are present.
PREREQUISITESPhysicists, engineers, environmental scientists, and anyone involved in thermal analysis or energy efficiency assessments will benefit from this discussion.
If the "body" is a light source not due to thermal radiation, then there is no ε. A CO2 laser will not emit the same power as a remote control, even if they are at the same temperature.amukher said:If the body only emits IR light, what should be the value of ε?
The emissivity is material dependent and surface roughness dependent. For example polished metal and foil of the same metal will have different emissivities, as shown here.amukher said:The energy emitted by a body in watts/m2 is = εσT4. In the case of a perfect black body, ε=1. If the body only emits IR light, what should be the value of ε?
amukher said:If the body only emits IR light, what should be the value of ε?
DrClaude said:If the "body" is a light source not due to thermal radiation, then there is no ε. A CO2 laser will not emit the same power as a remote control, even if they are at the same temperature.
The emissivity depends on the body shape (e.g how smooth it is) and the material. There's no easy way to predict them, they are basically empirical valuesamukher said:Let us say that the atmosphere blocks all visible light wavelengths and allows only IR wavelengths to reach the earth. The Earth would then be a source of thermal radiation. To calculate the heat emitted by the earth, I would need the value of ε.