How to Calculate the Gradient of a Separation Vector?

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    Separation Vector
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Discussion Overview

The discussion revolves around calculating the gradient of a separation vector, specifically focusing on the expression for the gradient of the reciprocal of its length. Participants explore the mathematical formulation and differentiation techniques involved in this calculation.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant presents the expression for the gradient of the reciprocal of the length of the separation vector, suggesting that Gradient(1/c) = -c'(hat)/c^2.
  • Another participant prompts for clarification on the initial work or derivation leading to the proposed expression.
  • A suggestion is made to express 1/c in terms of Cartesian coordinates and to differentiate using the chain rule, noting that the primed terms are constants during differentiation.
  • There is a clarification regarding the notation "hat," indicating it refers to the unit vector in the direction of the separation vector.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the derivation process or the initial expression, and multiple viewpoints regarding the differentiation approach and notation are present.

Contextual Notes

The discussion includes assumptions about the differentiation process and the interpretation of vector notation, which remain unresolved.

starbaj12
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Let c' be the separation vector from a fixed point(x'',y'',z'') to the point (x,y,z) and let c be its length. show that

Gradient(1/c) = -c'(hat)/c^2

Thnaks for the help
 
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your work?
 
begin by writing 1/c in terms of cartesian coordinates.

c = sqrt[(x - x`)^2 + (y - y`)^2 + (z - z`)^2]
1/c = ?

then differentiate using multiple applications of the chain rule. Remember that the primed terms are constant when differentiating respect to x, y or z. This was the part that confused me at the beginning as I didn't know how to differentiate those.
 
starbaj12 said:
Let c' be the separation vector from a fixed point(x'',y'',z'') to the point (x,y,z) and let c be its length. show that

Gradient(1/c) = -c'(hat)/c^2

Thnaks for the help

What is "hat"?
 
^

mathwizarddud said:
What is "hat"?

"hat" is ^

it means the unit vector in the direction of c' :smile:
 

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