How to calculate the impact energy of a door hitting a door

Click For Summary
To calculate the impact energy of a glass door slamming against a door stop, one must consider the door's dimensions, weight, and wind load. The door measures 1.5m by 3.0m, weighs 170kg, and experiences a wind load of 2.14kN/m^2. The impact force will vary based on the properties of the door stop and the door's movement upon impact, as the door does not stop instantaneously. A theoretical calculation could suggest an infinite force if the door stops abruptly, but in reality, the door's center of mass continues moving, leading to a twisting motion. Calculating the precise dynamics of the impact may require complex analysis beyond basic equations.
David Walker
Messages
1
Reaction score
0
Could someone help me with this problem?

I have a scenario where a glass door is being caught by the wind and slamming against a door stop and shattering. I would like to work out the impact energy of the door hitting the stop, and if possible an equivalent static force.

The door is 1.5m wide, 3.0m high and constructed of 15mm glass, (170kg total weight).
The wind load is 2.14kN/m^2
The door opens 90 degrees with the door stop 350mm from the pivot. The pivot is 100mm in from the edge of the door.

Thank you.
 

Attachments

Physics news on Phys.org
Can you find any relevant equations? Can you draw a free body diagram?
Do you think your employer would approve you seeking solutions to problems on their pad?
 
I don't believe it's possible to calculate a solution with just the info given.

The force will depend to a great extent on the properties of the door stop and the door. If you assume the door stops moving the instant it hits the stop then the calculated force is theoretically infinite. Obviously the door doesn't stop instantly. I suspect what happens is that the bottom of the door stops quickly but the centre of mass of the door continues and this twists the door. In effect you have a glass torsional "spring" that decelerates the door.

There is probably a way to calculate how the door moves when it hits the stop but it will be quite complicated - too hard for me!
 
I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

Similar threads

  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
3K
Replies
6
Views
5K
Replies
11
Views
6K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
4
Views
10K